If you are talking about Question 60, then one could use the answer choices but it is more work than doing it directly. One still would need to recognize that the measure of angle KPM is (11x)/2 and set this to equal to different answer choices and compute the value of x. Then with that value of x, one would need to the check if (4x+18) turns out to be equal to (11x)/2.

Yes, I just checked and the Reading answers are correct here. At least that is what I have in the answer official answer sheet. But I did have a wrong set on the main page where the link to this test is organized, I have fixed that one.

I have attached a screenshot from the official TIR of ACT 74F.

Can you explain 59 again? Why can’t sine theta be greater than 1 ? Do I need to know the unit circle for this? How can I use the given range of radian measures to help me solve? Thanks

Sorry for the delay. You can think of sin theta as the ratio of opposite to hypotenuse in a right triangle and this ratio is less than or equal to one. It is equal to one when the angle is 90 degrees. You can also use the unit circle approach, where sine of theta is equal to the y-coordinate of the point on the circle.

To satisfy the condition, $|\sin \theta| \geq 1$, the only way this will happen is if $\sin \theta$ is equal to $+1$ or $-1$, and these happen at $\pi/2$ and $-\pi/2$. These happen at the top and bottom of the unit circle.

Jan Altman says

Is there any other way to solve this?

Dabral says

If you are talking about Question 60, then one could use the answer choices but it is more work than doing it directly. One still would need to recognize that the measure of angle KPM is (11x)/2 and set this to equal to different answer choices and compute the value of x. Then with that value of x, one would need to the check if (4x+18) turns out to be equal to (11x)/2.

Liz Kelly says

41 needs to be explained in a different way. Need to understand the concept of ‘frequency chart’ and ‘cumulative number’.

Aniruddh Lodha says

The reading answers are completely wrong

Dabral says

Thank you for catching the mistake. I have fixed the answer sheet.

Jackie KESSLER says

are you sure the reading answers are fixed now?

Dabral says

Yes, I just checked and the Reading answers are correct here. At least that is what I have in the answer official answer sheet. But I did have a wrong set on the main page where the link to this test is organized, I have fixed that one.

I have attached a screenshot from the official TIR of ACT 74F.

Dabral

Beckie B says

Can you explain 59 again? Why can’t sine theta be greater than 1 ? Do I need to know the unit circle for this? How can I use the given range of radian measures to help me solve? Thanks

Dabral says

Hi Beckie,

Sorry for the delay. You can think of sin theta as the ratio of opposite to hypotenuse in a right triangle and this ratio is less than or equal to one. It is equal to one when the angle is 90 degrees. You can also use the unit circle approach, where sine of theta is equal to the y-coordinate of the point on the circle.

To satisfy the condition, $|\sin \theta| \geq 1$, the only way this will happen is if $\sin \theta$ is equal to $+1$ or $-1$, and these happen at $\pi/2$ and $-\pi/2$. These happen at the top and bottom of the unit circle.

I hope this makes sense.